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WBJEE · Maths · Continuity and Differentiability

\(\operatorname{Let} f(x)=\left\{\begin{array}{l}0, \text { if }-1 \leq x < 0 \\ 1, \text { if } x=0 \\ 2, \text { if } 0 < x \leq 1\end{array}\right.\) and let \(F(x)=\int_{-1}^{x} f(t) d t,-1 \leq x \leq 1\), then

  1. A \(\mathrm{F}\) is continuous function in \([-1,1]\)
  2. B \(F\) is discontinuous function in \([-1,1]\)
  3. C \(\mathrm{F}^{\prime}(\mathrm{x})\) exists at \(\mathrm{x}=0\)
  4. D \(\mathrm{F}^{\prime}(\mathrm{x})\) does not exists at \(\mathrm{x}=0\)
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Correct Answer

(D) \(\mathrm{F}^{\prime}(\mathrm{x})\) does not exists at \(\mathrm{x}=0\)

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Detailed explanation

\(f(x)=\left\{\begin{array}{ll}0 & -1 \leq x \(F(x)=\left\{\begin{array}{ll}0 & -1 \leq x \leq 0 \\ 2 x & 0 < x \leq 1\end{array}\right.\)
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