WBJEE · Maths · Binomial Theorem
If n is a positive integer, the value of \((2 n+1)^n C_0+(2 n-1)^n C_1+(2 n-3)^n C_2+\ldots .+1 \cdot{ }^n C_n\) is
- A \((n+1) 2^n\)
- B \(3^{\text {n }}\)
- C \(f^{\prime}(2)\) where \(f(x)=x^{n+1}\)
- D \((n+1) 2^{n+1}\)
Answer & Solution
Correct Answer
(C) \(f^{\prime}(2)\) where \(f(x)=x^{n+1}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Hint: } \sum_{r=0}^n(2 n+1-2 r)^n C_r \\ & =(2 n+1) \sum_{r=0}^n{ }^n C_r-2 \sum_{r=0}^n r \cdot{ }^n C_r \\ & =(2 n+1) \cdot 2^n-2 \cdot n \cdot 2^{n-1}=(n+1) \cdot 2^n \\ & \text { If } f(x)=x^{n+1} \Rightarrow f^{\prime}(2)=(n+1) \cdot…
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