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WBJEE · Maths · Sequences and Series

Let \(a, b, c, p, q\) and \(r\) be positive real numbers such that \(a, b\) and \(c\) are in GP and \(a^{p}=b^{q}=c^{r}\). Then,

  1. A \(p, q, r\) are in G.P.
  2. B \(p, q, r\) are in A.P.
  3. C \(p, q, r\) are in H.P.
  4. D \(p^{2}, q^{2}, r^{2}\) are in A.P.
Verified Solution

Answer & Solution

Correct Answer

(C) \(p, q, r\) are in H.P.

Step-by-step Solution

Detailed explanation

Let \(a^{p}=b^{4}=c^{r}=k\) \(\therefore \quad a=k^{1 / p}, b=k^{1 / q}, c=k^{1 / r}\) since, \(a, b, c\) are in \(\mathrm{GP} .\) \(\therefore\) \(\frac{b}{a}=\frac{c}{b}\) \(\frac{k^{1 / q}}{k^{1 / P}}=\frac{k^{1 / r}}{k^{1 / q}}\) \(k^{1 / q-1 / p}=k^{1 / r-1 / 4}\)…