WBJEE · Maths · Parabola
If the tangent to \(y^{2}=4 a x\) at the point \(\left(a t^{2}, 2 a t\right)\) where \(|t|>1\) is a normal to \(x^{2}-y^{2}=a^{2}\) at the point \((a \sec \theta, a \tan \theta),\) then
- A \(t=-\operatorname{cosec} \theta\)
- B \(t=-\sec \theta\)
- C \(t=2 \tan \theta\)
- D \(t=2 \cot \theta\)
Answer & Solution
Correct Answer
(C) \(t=2 \tan \theta\)
Step-by-step Solution
Detailed explanation
\(\left(a,\right.\)Equation of tangent to \(y^{2}=4 a x\) at \(\left(a t^{2}, 2 a t\right)\) will be \[ x-y t=-a t^{2} \] Also, equation of normal to \(x^{2}-y^{2}=a^{2}\) at \((a \sec \theta, a \tan \theta)\) will be \(\frac{x}{a \sec \theta}+\frac{y}{a \tan \theta}=2\)…
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