WBJEE · Maths · Limits
The value of \(\operatorname{Lt}_{x \rightarrow 0}\left(\frac{1+5 x^2}{1+3 x^2}\right)^{\frac{1}{x^2}}\) is
- A \(\mathrm{e}^2\)
- B \(\mathrm{e}\)
- C \(\frac{1}{\mathrm{e}}\)
- D \(\frac{1}{\mathrm{e}^2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{e}^2\)
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