WBJEE · Maths · Complex Number
The side \(A B\) of \(\triangle A B C\) is fixed and is of length \(2 a\) unit. The vertex moves in the plane such that the vertical angle is always constant and is \(\alpha\). Let \(x\)-axis be along \(A B\) and the origin be at \(A\). Then the locus of the vertex is
- A \(x^2+y^2+2 a x \sin \alpha+a^2 \cos \alpha=0\)
- B \(x^2+y^2-2 a x-2 a y \cot \alpha=0\)
- C \(x^2+y^2-2 a x \cos \alpha-a^2=0\)
- D \(x^2+y^2-a x \sin \alpha-\) ay \(\cos \alpha=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-2 a x-2 a y \cot \alpha=0\)
Step-by-step Solution
Detailed explanation
Let, \(c=z=x+i y\)…
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