WBJEE · Maths · Determinants
If \(\omega\) is an imaginary cube root of unity, then the value of the determinant \(\left|\begin{array}{ccc}1+\omega & 0 & -\omega \\ 1+\omega^{2} & \omega & -\omega^{2} \\ \omega+\omega^{2} & \omega & -\omega^{2}\end{array}\right|\) is
- A \(-2 \omega\)
- B \(-3 w^{2}\)
- C -1
- D 0
Answer & Solution
Correct Answer
(B) \(-3 w^{2}\)
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{ccc}1+\omega & \omega^{2} & -\omega \\ 1+\omega^{2} & \omega & -\omega^{2} \\ \omega+\omega^{2} & \omega & -\omega^{2}\end{array}\right|\)…
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