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WBJEE · Maths · Definite Integration

The points of extremum of \(\int_0^{x^2} \frac{t^2-5 t+4}{2+e^t} d t\) are

  1. A \(\pm 1\)
  2. B \(\pm 2\)
  3. C \(\pm 3\)
  4. D \(\pm \sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\pm 2\)

Step-by-step Solution

Detailed explanation

Hint: \(f(x)=\int_0^{x^2} \frac{t^2-5 t+4}{2+e^t} d t\)...(1) to find extremum points we solve \(f^{\prime}(x)=0\) so differentiating equation (i) using Newton Leibnitz Rule,…