WBJEE · Maths · Definite Integration
The points of extremum of \(\int_0^{x^2} \frac{t^2-5 t+4}{2+e^t} d t\) are
- A \(\pm 1\)
- B \(\pm 2\)
- C \(\pm 3\)
- D \(\pm \sqrt{2}\)
Answer & Solution
Correct Answer
(B) \(\pm 2\)
Step-by-step Solution
Detailed explanation
Hint: \(f(x)=\int_0^{x^2} \frac{t^2-5 t+4}{2+e^t} d t\)...(1) to find extremum points we solve \(f^{\prime}(x)=0\) so differentiating equation (i) using Newton Leibnitz Rule,…
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