WBJEE · Maths · Straight Lines
A ray of light along \(x+\sqrt{3}y=\sqrt{3}\) gets reflected upon reaching \(x\)-axis, the equation of the reflected ray is
- A \(y=x+\sqrt{3}\)
- B \(\sqrt{3} \mathrm{y}=\mathrm{x}-\sqrt{3}\)
- C \(y=\sqrt{3} x-\sqrt{3}\)
- D \(\sqrt{3} y=x-1\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3} \mathrm{y}=\mathrm{x}-\sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A} \equiv(\sqrt{3}, 0)\) Let, B \((0,1)\) \(\therefore \mathrm{B}^{\prime} \equiv(0,-1)\) \(\therefore\) Equation of \(\mathrm{AB}^{\prime}: \frac{\mathrm{y}-0}{0+1}=\frac{\mathrm{x}-\sqrt{3}}{\sqrt{3}-0} \Rightarrow \sqrt{3} \mathrm{y}=\mathrm{x}-\sqrt{3}\)
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