WBJEE · Physics · Laws of Motion
Work done for a certain spring when it is streched to 1mm from mean position is 10J amount of work that must be done on the spring to stretch it further by \(1 \mathrm{mm}\) is
- A \(30 \mathrm{J}\)
- B \(40 \mathrm{J}\)
- C \(10 \mathrm{J}\)
- D \(20 \mathrm{J}\)
Answer & Solution
Correct Answer
(A) \(30 \mathrm{J}\)
Step-by-step Solution
Detailed explanation
The work done in stretching the spring, \(W=\frac{1}{2} K x^{2}\) \(K=\) force constant of spring \(x=\) extension in length of the spring…
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