WBJEE · Maths · Application of Derivatives
If \(y=2 x^3-2 x^2+3 x-5\), then for \(x=2\) and \(\Delta x=0.1\) value of \(\Delta y\) is
- A 2.002
- B 1.9
- C 0
- D 09
Answer & Solution
Correct Answer
(B) 1.9
Step-by-step Solution
Detailed explanation
\(\text { Hints: } \frac{\mathrm{dy}}{\mathrm{dx}}=6 \mathrm{x}^2-4 \mathrm{x}+3 \quad \Delta \mathrm{y}=\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)_{\mathrm{x}-2} \Delta \mathrm{x}=1.9\)
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