WBJEE · Physics · Mathematics in Physics
Given \(\overrightarrow{\mathrm{C}}=\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{B}}\) and \(\overrightarrow{\mathrm{D}}=\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{A}}\). What is the angle between \(\overrightarrow{\mathrm{C}}\) and \(\overrightarrow{\mathrm{D}}\) ?
- A \(30^{\circ}\)
- B \(60^{\circ}\)
- C \(90^{\circ}\)
- D \(180^{\circ}\)
Answer & Solution
Correct Answer
(D) \(180^{\circ}\)
Step-by-step Solution
Detailed explanation
\(\vec{C}\) and \(\vec{D}\) are antiparellel since \(\vec{A} \times \vec{B}=-(\vec{B} \times \vec{A})\)
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