WBJEE · Maths · Basic of Mathematics
\(7^{2 n}+16 n-1(n \in N)\) is divisible by
- A 65
- B 63
- C 61
- D 64
Answer & Solution
Correct Answer
(D) 64
Step-by-step Solution
Detailed explanation
We have, \(7^{2 n}+16 n-1\) Put \(n=1,\) we get \(\begin{aligned} 7^{2}+16-1 & \\ =& 49+15 \\ =& 64 \end{aligned}\) which is divisible by 64.
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