WBJEE · Physics · Electromagnetic Waves
For a plane eletromagnetic wave, the electric field is given by \(\overrightarrow{\mathrm{E}}=90 \sin \left(0.5 \times 10^{3} \mathrm{x}+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{k} . \mathrm{v} / \mathrm{m} .\) The corresponding magnetic field \(\vec{B}\) will be
- A \(\vec{B}=3 \times 10^{-7} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \hat{i} \mathrm{~T}\)
- B \(\vec{B}=3 \times 10^{-7} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \hat{j} \mathrm{~T}\)
- C \(\vec{B}=27 \times 10^{9} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \hat{j} \mathrm{~T}\)
- D \(\overrightarrow{\mathrm{B}}=3 \times 10^{-7} \sin \left(0.5 \times 10^{3} \mathrm{x}+1.5 \times 10^{11} \mathrm{t}\right) \hat{\mathrm{k}} \mathrm{T}\)
Answer & Solution
Correct Answer
(B) \(\vec{B}=3 \times 10^{-7} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \hat{j} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\(E=90 \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} t\right) \hat{k} v / m\) Direction of propagation is \(-\hat{i}\) \(\& E_{0}=90\)…
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