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WBJEE · Physics · Electrostatics

A sphere of radius \(R\) has a volume density of charge \(\rho=k r,\) where \(r\) is the distance from the centre of the sphere and \(k\) is constant. The magnitude of the electric field which exists at the surface of the sphere is given by \(\left(\varepsilon_{0}=\right.\) permittivity of free space)

  1. A \(\frac{4 \pi k R^{4}}{3 \varepsilon_{0}}\)
  2. B \(\frac{k R}{3 e_{0}}\)
  3. C \(\frac{4 \pi k R}{\varepsilon_{0}}\)
  4. D \(\frac{k R^{2}}{4 \varepsilon_{0}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{k R^{2}}{4 \varepsilon_{0}}\)

Step-by-step Solution

Detailed explanation

By Gauss's theorem…
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