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WBJEE · Maths · Definite Integration

\(\lim _{n \rightarrow \infty} \frac{\sqrt{1}+\sqrt{2}+\ldots+\sqrt{n-1}}{n \sqrt{n}}\) is equal to

  1. A \(\frac{1}{2}\)
  2. B \(\frac{1}{3}\)
  3. C \(\frac{2}{3}\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{2}{3}\)

Step-by-step Solution

Detailed explanation

\(\lim _{n \rightarrow \infty} \frac{\sqrt{1}+\sqrt{2}+\ldots+\sqrt{n-1}}{n \sqrt{n}}\) \(=\lim _{n \rightarrow \infty}\left(\frac{\sqrt{1}+\sqrt{2}+\ldots+\sqrt{n-1}+\sqrt{n}}{n \sqrt{n}}-\frac{n}{n \times n}\right)\)…