WBJEE · Maths · Hyperbola
The equation of the directrices of the hyperbola \(3 x^{2}-3 y^{2}-18 x+12 y+2=0\) is
- A \(x=3 \pm \sqrt{\frac{13}{6}}\)
- B \(x=3 \pm \sqrt{\frac{6}{13}}\)
- C \(x=6 \pm \sqrt{\frac{13}{3}}\)
- D \(x=6 \pm \sqrt{\frac{3}{13}}\)
Answer & Solution
Correct Answer
(A) \(x=3 \pm \sqrt{\frac{13}{6}}\)
Step-by-step Solution
Detailed explanation
Given equation is \[ 3 x^{2}-3 y^{2}-18 x+12 y+2=0 \] It can be written as \(\frac{(x-3)^{2}}{\left(\sqrt{\frac{13}{3}}\right)^{2}}-\frac{(y-2)^{2}}{\left(\sqrt{\frac{13}{3}}\right)^{2}}=1\)…
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