WBJEE · Chemistry · Ionic Equilibrium
Solubility products \(\left(\mathrm{K}_{\mathrm{sp}}\right)\) of the salts of types \(\mathrm{MX}, \mathrm{MX}_{2}\) and \(\mathrm{M}_{3} \mathrm{X}\) at temperature \(\mathrm{T}\) are \(4.0 \times 10^{-8}, 3.2 \times 10^{-14}\) and \(2.7 \times\) \(10^{-15}\) respectively. Solubilities (in \(\mathrm{mol} \mathrm{dm}^{-3}\) ) of the salts at temperature \(\mathrm{T}\) are in the order
- A \(\quad M X>M X_{2}>M_{3} X\)
- B \(M_{3} X>M X_{2}>M X\)
- C \(\mathrm{MX}_{2}>\mathrm{M}_{3} \mathrm{X}>\mathrm{MX}\)
- D \(\mathrm{MX}>\mathrm{M}_{3} \mathrm{X}>\mathrm{MX}_{2}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{MX}>\mathrm{M}_{3} \mathrm{X}>\mathrm{MX}_{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} \mathrm{MX} & \mathrm{K}_{\mathrm{sp}}=4 \times 10^{-8}=\mathrm{S}^{2} \therefore \mathrm{S}=2 \times 10^{-4} \\ \mathrm{MX}_{2} & \mathrm{~K}_{\mathrm{sp}}=3.2 \times 10^{-14}=4 \mathrm{~S}^{3} \end{array}\)…
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