WBJEE · Chemistry · Ionic Equilibrium
The pH of \(10^{-4} \mathrm{M}\) KOH solution will be
- A 4
- B 11
- C 10.5
- D 10
Answer & Solution
Correct Answer
(D) 10
Step-by-step Solution
Detailed explanation
\(10^{-4} \mathrm{M} \mathrm{KOH}=10^{-4} \mathrm{M}\left[\mathrm{OH}^{-}\right]\) We know that \[ \left.\left[\mathrm{H}^{+}\right] \mathrm{IOH}^{-1}\right]=1 \times 10^{-14} \]…
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