WBJEE · Chemistry · Chemical Kinetics
The half-life of \(C^{14}\) is 5760 years. For a \(200 \mathrm{mg}\) sample of \(\mathrm{C}^{14}\), the time taken to change to \(25 \mathrm{mg}\) is
- A 11520 years
- B 23040 years
- C 5760 years
- D 17280 years
Answer & Solution
Correct Answer
(D) 17280 years
Step-by-step Solution
Detailed explanation
Given. Half-life of \(\mathrm{C}^{4}, t_{1 / 2}=5760\) years Initial concentration of sample of \(\mathrm{C}^{4}, \mathrm{N}_{0}=200 \mathrm{mg}\) Final concentration of sample of \(\mathrm{C}^{4}, \mathrm{N}_{1}=2 \mathrm{S} \mathrm{mg}\) The given decay is radioactive and all…
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