WBJEE · Chemistry · Some Basic Concepts of Chemistry
The mole fraction of ethanol in water is \(0.08\). Its molality is
- A \(6.32 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- B \(4.83 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- C \(3.82 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- D \(2.84 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Answer & Solution
Correct Answer
(B) \(4.83 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Step-by-step Solution
Detailed explanation
Hint: \(\begin{aligned} \text { Molality } &=\frac{\mathrm{x}_{\mathrm{EtOH}}}{\mathrm{x}_{\mathrm{H}_{2} \mathrm{O}}} \times \frac{1000}{\mathrm{MW}_{\text {solvent }}} \\ &=\frac{0.08}{0.92} \times \frac{1000}{18} \\ &=4.83 \mathrm{~mol} \mathrm{~kg}^{-1} \end{aligned}\)
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