WBJEE · Maths · Definite Integration
The value of the integral \(\int_{-1}^{1}\left\{\frac{x^{2015}}{e^{\mid x \mid}\left(x^{2}+\cos x\right)}+\frac{1}{e^{\mid{x} \mid}}\right\} d x\) is equal to
- A 0
- B \(1-e^{-1}\)
- C \(2 e^{-1}\)
- D \(2\left(1-e^{-1}\right)\)
Answer & Solution
Correct Answer
(D) \(2\left(1-e^{-1}\right)\)
Step-by-step Solution
Detailed explanation
Let \(I=\int_{-1}^{1}\left\{\frac{x^{2015}}{\left(e^{\mid x\mid} \left(x^{2}+\cos x\right)\right.}+\frac{1}{e^{|x|}}\right\} d x\)…
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