WBJEE · Chemistry · Chemical Kinetics
The following graph shows how \(\mathrm{T}_{1 / 2}\) (half-life) of a reactant \(\mathrm{R}\) changes with the initial reactant concentration \(a_0\).

The order of the reaction will be :
- A \(0\)
- B \(1\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(t_{1 / 2} \propto \frac{1}{a^{n-1}}\) Hence (C)
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