WBJEE · Chemistry · Electrochemistry
At temperature of \(298 \mathrm{K}\), the emf of the following electrochemical cell. \(\mathrm{Ag}(\mathrm{s})\left|\mathrm{Ag}^{+*}(0.1 \mathrm{M}) \| \mathrm{Zn}^{2 +}(0.1 \mathrm{M})\right| \mathrm{Zn}(\mathrm{s})\) will be (Given, \(E^{\prime \prime}\) call \(=-1.562 \mathrm{V}\) )
- A \(-1.532 \mathrm{V}\)
- B \(-1.503 V\)
- C \(1.532 \mathrm{V}\)
- D \(-3.06 V\)
Answer & Solution
Correct Answer
(A) \(-1.532 \mathrm{V}\)
Step-by-step Solution
Detailed explanation
From the given cell, the cell reaction is \(2 \mathrm{Ag}(s)+Z \mathrm{n}^{2+}(01 \mathrm{M}) \longrightarrow\) \(2 \mathrm{Ag}^{+}(0.1 \mathrm{M})+\mathrm{Zn}(s)\) The Nemst equation is,…
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