WBJEE · Chemistry · Coordination Compounds
Cold ferrous sulphate solution on absorptive of NO develops brown colour due to the formation of
- A paramagnetic \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right] \mathrm{SO}_{4}\)
- B diamagnetic \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\left(\mathrm{N}_{3}\right)\right] \mathrm{SO}_{4}\)
- C paramagnetic \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\left(\mathrm{NO}_{3}\right)\right]\left[\mathrm{SO}_{4} \mathrm{l}_{2}\right.\)
- D diamagnetic \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\left(\mathrm{SO}_{4}\right)\right] \mathrm{NO}_{3}\)
Answer & Solution
Correct Answer
(A) paramagnetic \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right] \mathrm{SO}_{4}\)
Step-by-step Solution
Detailed explanation
Cold FeSO, solution on absorption of NO develops brown colour due to the formation of \([Fe(H_{2}O)_{5}(NO)]SO_4\) \(\mathrm{FeSO}_{4}+\mathrm{NO}+5 \mathrm{H}_{2} \mathrm{O} \rightarrow [Fe(H_{2}O)_{5}(NO)]SO_4\) This complex has 3.89 BM magnetic moment shows that it has 3…
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