WBJEE · Maths · Application of Derivatives
Let \(y=f(x)=2 x^{2}-3 x+2\). The differential of \(y\) when \(x\) changes from 2 to \(1.99\) is
- A \(0.01\)
- B \(0.18\)
- C \(-0.05\)
- D \(0.07\)
Answer & Solution
Correct Answer
(C) \(-0.05\)
Step-by-step Solution
Detailed explanation
Hint: \(\Delta x=-0.01 \Rightarrow \Delta y=f^{\prime}(x) \Delta x \Rightarrow \Delta y=f^{\prime}(2)(-0.01) \Rightarrow \Delta y=-5 \times 0.01 \Rightarrow \Delta y=-0.05\)
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