WBJEE · Chemistry · General Organic Chemistry
In a mixture, two enantioners are found to be present in 85\% and \(15 \%\) respectively. The enantiomeric. excess (ee) is
- A \(85 \%\)
- B \(15 \%\)
- C \(70 \%\)
- D \(60 \%\)
Answer & Solution
Correct Answer
(C) \(70 \%\)
Step-by-step Solution
Detailed explanation
\(15 \%\) will form racemic mixture with another \(15 \%\). Hence. the enantiomeric excess is \(=(85-15)=70 \%\)
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