WBJEE · Maths · Straight Lines
Transforming to parallel axes through a point \((p, q), \quad\) the \(\quad\) equation \(2 x^{2}+3 x y+4 y^{2}+x+18 y+25=0\) becomes
\(2 x^{2}+3 x y+4 y^{2}=1 .\) Then
- A \(p=-2, q=3\)
- B \(p=2, q=-3\)
- C \(p=3, q=-4\)
- D \(p=-4, q=3\)
Answer & Solution
Correct Answer
(B) \(p=2, q=-3\)
Step-by-step Solution
Detailed explanation
Given equations are \[ \begin{array}{r} 2 x^{2}+3 x y+4 y^{2}+x+18 y+25=0 ...(i)\\ 2 x^{2}+3 x y+4 y^{2}+1=0 ....(ii) \end{array} \] Let the origin be transferred to \((p, q)\) axes being parallel to the previous axes; then the equation (i) becomes.…
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