WBJEE · Chemistry · Redox Reactions
\(0.126 \mathrm{g}\) of an acid is needed to completely neutralise \(20 \mathrm{mL} 0.1\) (N) NaOH solution. The equivalent weight of the acid is
- A 53
- B 40
- C 45
- D 63
Answer & Solution
Correct Answer
(D) 63
Step-by-step Solution
Detailed explanation
\(\because\) Number of milli equivalents of NaOH \(\left(n^{\prime}\right)=N V=0.1 \times 20=2\) \(\therefore\) Number of equivalent \(=0.002\) For Neutralisation Number of equivalent of base (NaOH) Number of equivalent of acid \(0.002=\frac{W}{E}=\frac{0.126}{E}\)…
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