WBJEE · Maths · Determinants
Let \(A=\left(\begin{array}{cc}x+2 & 3 x \\ 3 & x+2\end{array}\right), B=\left(\begin{array}{cc}x & 0 \\ 5 & x+2\end{array}\right)\). Then
all solutions of the equation det \((A B)=0\) is
- A 1,-1,0,2
- B 1,4,0,-2
- C 1,-1,4,3
- D -1,4,0,3
Answer & Solution
Correct Answer
(B) 1,4,0,-2
Step-by-step Solution
Detailed explanation
We know that, \(\operatorname{det}(A B)=\) det \((A)\) det \((B)\) \(\therefore\) \(\operatorname{det}(A B)=0\) \(\Rightarrow\) det\((A) \cdot\) det \((B)=0\)…
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