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WBJEE · Chemistry · Structure of Atom

\({ }_5 \mathrm{~B}^{10}+{ }_2 \mathrm{He}^4 \rightarrow \mathrm{X}+{ }_{\mathrm{o}} \mathrm{n}^1\)

In the above nuclear reaction ' X ' will be

  1. A \({ }_7 \mathrm{~N}^{14}\)
  2. B \({ }_7 \mathrm{~N}^{13}\)
  3. C \({ }_6 \mathrm{C}^{12}\)
  4. D \({ }_7 \mathrm{~N}^{14}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \({ }_7 \mathrm{~N}^{13}\)

Step-by-step Solution

Detailed explanation

\({ }_5 \mathrm{~B}^{10}+{ }_2 \mathrm{He}^4 \longrightarrow{ }_b^a \mathrm{x}+{ }_0 \mathrm{n}^1\) Balancing atomic numbers, we have \(\begin{aligned} & 5+2=\mathrm{b}+0 \\ & \therefore \mathrm{~b}=7 \end{aligned}\) Balancing mass numbers; we have…