WBJEE · Chemistry · Structure of Atom
\({ }_5 \mathrm{~B}^{10}+{ }_2 \mathrm{He}^4 \rightarrow \mathrm{X}+{ }_{\mathrm{o}} \mathrm{n}^1\)
In the above nuclear reaction ' X ' will be
- A \({ }_7 \mathrm{~N}^{14}\)
- B \({ }_7 \mathrm{~N}^{13}\)
- C \({ }_6 \mathrm{C}^{12}\)
- D \({ }_7 \mathrm{~N}^{14}\)
Answer & Solution
Correct Answer
(B) \({ }_7 \mathrm{~N}^{13}\)
Step-by-step Solution
Detailed explanation
\({ }_5 \mathrm{~B}^{10}+{ }_2 \mathrm{He}^4 \longrightarrow{ }_b^a \mathrm{x}+{ }_0 \mathrm{n}^1\) Balancing atomic numbers, we have \(\begin{aligned} & 5+2=\mathrm{b}+0 \\ & \therefore \mathrm{~b}=7 \end{aligned}\) Balancing mass numbers; we have…
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