WBJEE · Chemistry · Electrochemistry
The equivalent conductance of \(\mathrm{NaCl}, \mathrm{HCl}\) and \(\mathrm{CH}_3 \mathrm{COONa}\) at infinite dilution are \(126.45,426.16\) and 91 \(\mathrm{ohm}^{-1} \mathrm{~cm}^2 \mathrm{eq}^{-1}\) respectively at \(25^{\circ} \mathrm{C}\). The equivalent conductance of acetic acid (at infinite dilution) would be
- A \(461.61 \mathrm{~ohm}^{-1} \mathrm{~cm}^2 \mathrm{~eq}^{-1}\)
- B \(390.71 \mathrm{~ohm}^{-1} \mathrm{~cm}^2 \mathrm{~eq}^{-1}\)
- C cannot be determined from the given data
- D \(208.71 \mathrm{~ohm}^{-1} \mathrm{~cm}^2 \mathrm{~eq}^{-1}\)
Answer & Solution
Correct Answer
(B) \(390.71 \mathrm{~ohm}^{-1} \mathrm{~cm}^2 \mathrm{~eq}^{-1}\)
Step-by-step Solution
Detailed explanation
Hint : According to Kohlrausch's law…
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