TS EAMCET · Physics · Electromagnetic Induction
A circular coil consists 70 closely wound turns and has a radius of \(10 \mathrm{~cm}\). An externally produced magnetic field of magnitude \(2 \times 10^{-3} \mathrm{~T}\) is applied perpendicular to the coil. The net flux through the coil is found to vanish when the current in the coil is \(2.2 \mathrm{~A}\). The inductance of the coil is
- A \(2 \mathrm{mH}\)
- B \(3 \mathrm{mH}\)
- C \(4 \mathrm{mH}\)
- D \(1.5 \mathrm{mH}\)
Answer & Solution
Correct Answer
(A) \(2 \mathrm{mH}\)
Step-by-step Solution
Detailed explanation
Given, number of turns in the circular coil, \(N=70, r=10 \mathrm{~cm}=10^{-1} \mathrm{~m}\) \(B=2 \times 10^{-3} \mathrm{~T}\) \(\theta=0^{\circ}\) Magnetic flux, \(\phi=N B A \cos \theta\) \(=70 \times 2 \times 10^{-3} \times \pi r^2 \times \cos 0^{\circ}\)…
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