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TS EAMCET · Physics · Mechanical Properties of Solids

Two metal wires \(A\) and \(B\) have length \(L\) and \(3 L\) respectively. The radius of cross-sectional circular area of wire \(A\) and \(B\) are \(R\) and \(2 R\), respectively. These wires are joined end to end along their axis. When one end of the combined system is fixed and other end is pulled with a constant force \(F\), the elongation in both the wires is equal. If \(Y_A\) and \(Y_B\) are Young's modulus of wire \(A\) and \(B\), then the \(Y_B / Y_A\) is

  1. A \(\frac{3}{4}\)
  2. B \(\frac{4}{3}\)
  3. C \(\frac{2}{3}\)
  4. D \(\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{3}{4}\)

Step-by-step Solution

Detailed explanation

For metal wire \(A, L_A=L, R_A=R\) For metal wire \(B, L_B=3 L, R_B=2 R\) When the ends of the of metal wire \(A\) and \(B\) are joined and pulled with a constant force \(F\) after fixing the one end of combined system, then change in length of wire \(A\) and \(B\) is same.…
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