TS EAMCET · Physics · Mathematics in Physics
If the component of the vector \(\vec{A}\) along the vector \(\vec{B}\) is twice the component of \(\vec{B}\) along \(\vec{A}\), then the ratio of magnitudes of vectors \(\vec{A}\) and \(\vec{B}\) is
- A \(1: 2\)
- B \(3: 2\)
- C \(2: 1\)
- D \(3: 1\)
Answer & Solution
Correct Answer
(C) \(2: 1\)
Step-by-step Solution
Detailed explanation
\(\frac{\vec{A} \cdot \vec{B}}{|\vec{B}|} = 2 \frac{\vec{A} \cdot \vec{B}}{|\vec{A}|}\) \(\frac{1}{|\vec{B}|} = \frac{2}{|\vec{A}|}\) \(\frac{|\vec{A}|}{|\vec{B}|} = \frac{2}{1}\)
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