TS EAMCET · Physics · Ray Optics
The two surfaces of a concave lens, made of glass of refractive index 1.5 have the same radii of curvature \(R\). It is now immersed in a medium of refractive index 1.75 , then the lens
- A becomes a convergent lens of focal length \(3.5 R\)
- B becomes a convergent lens of focal length \(3.0 R\)
- C changes as a divergent lens of focal length \(3.5 R\)
- D changes as a divergent lens of focal length \(3.0 R\)
Answer & Solution
Correct Answer
(A) becomes a convergent lens of focal length \(3.5 R\)
Step-by-step Solution
Detailed explanation
From lens maker's formula \( \frac{1}{f}=\left({ }_g^m \mu-1\right)\left(\frac{1}{R_1}-\frac{1}{R_2}\right) \) Now, \(\quad{ }_g^m \mu=\frac{g \mu}{{ }_m \mu}=\frac{1.5}{1.75}\) For concave lens as shown in the figure, in this case \( R_1=-R \text { and } R_2=+R \)…
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