TS EAMCET · Physics · Magnetic Effects of Current
A current \(I\) flows in a straight wire bent in the shape of a quarter ring of radius \(R\) as shown in figure. The magnetic field induction \(B\) at point \(O\) is
- A \(\frac{\mu_0 l}{4 R}\)
- B \(\frac{\mu_0 I}{8 R}\)
- C \(\frac{\mu_0 l}{2 R}\)
- D \(\frac{\mu_0 l}{6 R}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu_0 I}{8 R}\)
Step-by-step Solution
Detailed explanation
Magnetic field at centre of a complete current carrying circular loop is \(B=\frac{\mu_0 I}{2 R}\) For one quarter of loop, \(B=\frac{1}{4} \times \frac{\mu_0 I}{2 R}=\frac{1}{8}\left(\frac{\mu_0 I}{R}\right) \mathrm{T}\)
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