TS EAMCET · Physics · Work Power Energy
Consider a particle is moving with a minimum speed \(v\) at highest point of vertical circle of radius \(R\). If the radius of the circle doubled the corresponding minimum speed will be
- A \(V\)
- B \(\frac{v}{\sqrt{2}}\)
- C \(\sqrt{3} v\)
- D \(\sqrt{2} v\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2} v\)
Step-by-step Solution
Detailed explanation
When a particle moves along a vertical circle, then it has its minimum speed at the highest point of the vertical circle and in this case it just completes the loop. The minimum speed is…
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