TS EAMCET · Physics · Electromagnetic Waves
If the peak value of the magnetic field of an electromagnetic wave is \(30 \times 10^{-9} \mathrm{~T}\), then the peak value of the electric. field is
- A \(3 \mathrm{Vm}^{-1}\)
- B \(12 \mathrm{Vm}^{-1}\)
- C \(6 \mathrm{Vm}^{-1}\)
- D \(9 \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(D) \(9 \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
For EM wave, \(\mathrm{B}_{\mathrm{o}}=30 \times 10^{-9} \mathrm{~T}, \mathrm{C}=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) \(\therefore\) Peak value of electric field is \(E_0=C B_0={ }^{\prime} 3 \times 10^8 \times 30 \times 10^{-9}=9 \mathrm{Vm}^{-1}\)
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