TS EAMCET · Physics · Waves and Sound
When a sound wave of wavelength \(\lambda\) is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
- A \(\lambda\)
- B \(\frac{\lambda}{2}\)
- C \(\frac{\lambda}{2 \pi}\)
- D \(\frac{\lambda}{4 \pi}\)
Answer & Solution
Correct Answer
(C) \(\frac{\lambda}{2 \pi}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & v_{\max }=v \\ & \Rightarrow \quad A \omega=v \\ & \Rightarrow \quad A \times 2 \pi v=v \lambda \\ & A=\frac{\lambda}{2 \pi} \\ & \end{aligned}\)
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