TS EAMCET · Physics · Nuclear Physics
The mass defect in a particular nuclear reaction is \(0.3 \mathrm{~g}\). The amount of energy liberated in kilowatt hour is : (Velocity of light \(=3 \times 10^8\) )
- A \(1.5 \times 10^6\)
- B \(2.5 \times 10^6\)
- C \(3 \times 10^6\)
- D \(7.5 \times 10^6\)
Answer & Solution
Correct Answer
(D) \(7.5 \times 10^6\)
Step-by-step Solution
Detailed explanation
\(\Delta m=0.3 \mathrm{~g}\) \(=0.3 \times 10^{-3} \mathrm{~kg}=3 \times 10^{-4} \mathrm{~kg}\) Energy liberated, \(E=\Delta m c^2\) \(=3 \times 10^{-4} \times\left(3 \times 10^8\right)^2\) \(=3 \times 10^{-4} \times 9 \times 10^{16}\) \(=27 \times 10^{12} \mathrm{~J}\)…
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