TS EAMCET · Physics · Magnetic Effects of Current
Two long straight parallel wires carry currents of 8 A and 10 A in opposite directions. If the distance of separation between the wires is 9 cm, then the net magnetic field at a point between the two wires, which is at a perpendicular distance of 4 cm from the wire carrying 8 A current is
- A Zero
- B \(4 \times 10^{-5} \mathrm{~T}\)
- C \(8 \times 10^{-5} \mathrm{~T}\)
- D \(12 \times 10^{-5} \mathrm{~T}\)
Answer & Solution
Correct Answer
(C) \(8 \times 10^{-5} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\(r_1 = 4 \, \mathrm{cm} = 0.04 \, \mathrm{m}\) \(r_2 = 9 \, \mathrm{cm} - 4 \, \mathrm{cm} = 5 \, \mathrm{cm} = 0.05 \, \mathrm{m}\) \(B_1 = \frac{\mu_0 I_1}{2 \pi r_1} = \frac{4 \pi \times 10^{-7} \times 8}{2 \pi \times 0.04} = 4 \times 10^{-5} \, \mathrm{T}\)…
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