TS EAMCET · Physics · Work Power Energy
A ball moves one-fourth \(\left(\frac{1^{\text {th }}}{4}\right)\) of a circle of radius \(R\) in time \(T\). Let \(v_1\) and \(v_2\) be the magnitudes of mean speed and mean velocity vector. The ratio \(\frac{v_1}{v_2}\) will be
- A \(\frac{\pi}{2}\)
- B \(\frac{3}{\pi}\)
- C \(\frac{2}{\sqrt{3} \pi}\)
- D \(\frac{\pi}{2 \sqrt{2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{2 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Key idea Mean speed of a moving body, \( v_{\mathrm{rms}}=\frac{\text { total distance }}{\text { total time taken }} \) Mean velocity vector for a moving body, \( v_{w v}=\frac{\text { total displacement }}{\text { total time taken }} \) A ball moving in a circular arc is shown…
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