TS EAMCET · Physics · Current Electricity
When a potentiometer is connected between the points \(\mathrm{A}\) and \(\mathrm{B}\) as shown in the circuit, balance point is obtained at \(64 \mathrm{~cm}\). When it is cornected between \(\mathrm{A}\) and \(\mathrm{C}\), the balance point is \(8 \mathrm{~cm}\). If the potentiometer is connected between \(\mathrm{B}\) and \(\mathrm{C}\) the balance point will be
- A \(8cm\)
- B \(56cm\)
- C \(64cm\)
- D \(72cm\)
Answer & Solution
Correct Answer
(B) \(56cm\)
Step-by-step Solution
Detailed explanation
Let the pot-ntial gradient of the potentiometer be \(\mathrm{x}\). \(\begin{aligned} & x=\frac{E_1}{64} \\ & \Rightarrow E_1=64 x ... (i) \end{aligned}\) When it is connected between \(\mathrm{A}\) and \(\mathrm{C}\) \(\mathrm{E}_1-\mathrm{E}_2=8 \mathrm{x}... (ii)\) Solving…
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