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TS EAMCET · Physics · Electromagnetic Waves

In a plane EM wave the electric field oscillates sinusoidally at a frequency of \(30 \mathrm{MHz}\) and amplitude \(150 \mathrm{~V} / \mathrm{m}\). Identify the correct expression of \(\overline{\mathrm{B}}\) assuming the wave is propagating along \(x\)-axis and is oscillating along \(y\)-axis.

  1. A \(5 \times 10^{-7} \sin \left[\frac{x}{3}-6 \times 10^{+7} t\right] \hat{z} \mathrm{~T}\)
  2. B \(5 \times 10^{-7} \sin \left[\pi\left(\frac{x}{5}-6 \times 10^{+7} t\right)\right] \hat{z} \mathrm{~T}\)
  3. C \(5 \times 10^{-7} \sin \left[\pi\left(\frac{x}{10}-3 \times 10^{+7} t\right)\right] \hat{z} \mathrm{~T}\)
  4. D \(5 \times 10^{-7} \sin \left[\pi\left(\frac{2 x}{5}-6 \times 10^{+8} t\right)\right] \hat{z} \mathrm{~T}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(5 \times 10^{-7} \sin \left[\pi\left(\frac{x}{5}-6 \times 10^{+7} t\right)\right] \hat{z} \mathrm{~T}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & B_0=\frac{E_0}{C}=\frac{150}{3 \times 10^8}=5 \times 10^{-7} \\ & f=30 \mathrm{MHz}=30 \times 10^6 \mathrm{~Hz} \\ & \omega=60 \pi \times 10^6 \mathrm{~Hz}, \mathrm{~K}=\frac{\omega}{\mathrm{C}}=\frac{\mathrm{x}}{5} \end{aligned}\) as…
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