TS EAMCET · Physics · Motion In One Dimension
Consider a vechicle moving with a velocity \(54 \mathrm{~km} / \mathrm{h}\). At a distance of \(400 \mathrm{~m}\), from the traffic light brakes are applied. The acceleration of the vehicle, after the application of brakes is \(-0.3 \mathrm{~m} / \mathrm{s}^2\). The vehicle's position relative to the traffic light is
- A \(25 \mathrm{~m}\)
- B \(375 \mathrm{~m}\)
- C \(425 \mathrm{~m}\)
- D \(30 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(25 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, initial velocity, \[ \begin{aligned} & u=54 \mathrm{~km} / \mathrm{h}=54 \times \frac{5}{18} \mathrm{~m} / \mathrm{s} \\ & u=15 \mathrm{~m} / \mathrm{s} \end{aligned} \] Distance of signal from vehicle, \(d=400 \mathrm{~m}\) acceleration,…
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