TS EAMCET · Physics · Dual Nature of Matter
The work done to accelerate an electron from rest so that it can have a de Broglie wavelength of \(6600 Å\) is nearly
(Planck's constant \(=6.6 \times 10^{-34} \mathrm{Js}\) and mass of electron \(=9 \times 10^{-31} \mathrm{~kg}\) )
- A \(5.56 \times 10^{-25} \mathrm{eV}\)
- B 1.88 eV
- C \(5.56 \times 10^{-25} \mathrm{~J}\)
- D 1.88 J
Answer & Solution
Correct Answer
(C) \(5.56 \times 10^{-25} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(p = \frac{h}{\lambda}\) \(p = \frac{6.6 \times 10^{-34} \mathrm{Js}}{6600 \times 10^{-10} \mathrm{~m}} = 1 \times 10^{-27} \mathrm{~kg~m/s}\) \(K = \frac{p^2}{2m}\)…
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