TS EAMCET · Physics · Nuclear Physics
An element consists of a mixture of three isotopes \(A\), \(B\) and \(C\) of masses \(m_1, m_2\) and \(m_3\) respectively. If the relative abundances of the three isotopes \(A, B\) and \(C\) is in the ratio \(2: 3: 5\), the average mass of the element is
- A \(0.2 m_1+0.3 m_2+0.5 m_3\)
- B \(2 m_1+3 m_2+5 m_3\)
- C \(0.4 m_1+0.6 m_2+m_3\)
- D \(4 m_1+6 m_2+10 m_3\)
Answer & Solution
Correct Answer
(A) \(0.2 m_1+0.3 m_2+0.5 m_3\)
Step-by-step Solution
Detailed explanation
If the relative abundances of the three isotopes A, B and \(C\), (masses \(m_1, m_2\) and \(m_3\) ) is in the ratio \(2: 3: 5\), the average mass of the element is \(0.2 \mathrm{~m}_1+0.3 \mathrm{~m}_2+0.5 \mathrm{~m}_3\)
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