TS EAMCET · Physics · Motion In Two Dimensions
A projectile is thrown into air with velocity \(15 \mathrm{~m} / \mathrm{s}\) at an angle \(30^{\circ}\) with the horizontal. After what time its direction of motion is perpendicular to its initial direction? (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(3 \mathrm{~s}\)
- B \(2 \mathrm{~s}\)
- C \(0.5 \mathrm{~s}\)
- D \(1.5 \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(3 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
The given projectile motion is as shown in figure, Let \(t\) be the time after which the initial direction is perpendicular to its direction of motion. As, velocity of a projectile has two components. So, its initial velocity is given by…
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