TS EAMCET · Physics · Waves and Sound
Two trucks heading in opposite directions each with speed \(0.1 u\), approach each other. The speed of the sound is \(u\). The driver of first truck sounds his horn of frequency \(495 \mathrm{~Hz}\). Let \(v_1\) and \(v_2\) are the frequencies heard by the driver of second truck, when the trucks approach each other and when the trucks have passed each other. The magnitude of \(v_1-v_2\) is
- A \(150 \mathrm{~Hz}\)
- B \(200 \mathrm{~Hz}\)
- C \(220 \mathrm{~Hz}\)
- D \(270 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(B) \(200 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
Given, frequency heard by first truck driver, \(v=495 \mathrm{~Hz}\) Velocity of sound, \(v_s=u\) Velocity of trucks, \(v_1=v_2=0.1 u\) In the first case, when two trucks are approaching each other: The frequency heard by second truck driver,…
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